Howling:Time travel theory: Difference between revisions
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In series 6, if the doctor travels back to the wedding and before the wedding he'll be there with Amy.. he wont have to bring himself back anymore![[Special:Contributions/94.187.77.178|94.187.77.178]] 11:38, August 3, 2010 (UTC) | In series 6, if the doctor travels back to the wedding and before the wedding he'll be there with Amy.. he wont have to bring himself back anymore![[Special:Contributions/94.187.77.178|94.187.77.178]] 11:38, August 3, 2010 (UTC) | ||
Here is your problem: | |||
You say the timeline looks like this | |||
/C | |||
/ | |||
O A B / | |||
------------------- | |||
\ | |||
\ | |||
\D | |||
but in this timeline, the Doctor has to either exist from O to B or not exist from O to B, in other words, the Doctor's personal timeline can only be BC or BD, and cannot start at any point before B. The reason behind it is that OB must be in the same state, if it isn't, then there are two timelines in its place. You cannot fit in 2 histories on the same timeline. | |||
Now look at a more complicated model which you may be thinking but you couldn't conceptualize it yourself, | |||
\O1 /C | |||
\ / | |||
\ A B / | |||
--------------- | |||
/ \ | |||
/ \ | |||
/O2 \D | |||
where O1C represents the existence state and O2D represents the inexistence state, and AB is the part where 2 timeline converge. This is probably what you want to say in that O1A and O2A represents respective histories from the timeline with the Doctor's existence and without his existence, and AB represents Big Bang 2 to Amy's wedding. Big problem here: AB can't exist. Why? It's not just the fact that AB are in mixed states, but the fact that O1B <> O2B implies that there are 2 separate timelines in place of AB...simply put, at point A, the timeline is built upon O1 or O2, so the complete timeline is O1C and O2D...that means even if Doctor from C travels to point A, he is on the timeline O1C and not O2D, the opposite also apply for Doctor from D. Since O1A and O2A are different, AB cannot be simply one timeline. As A is built either on O1 or O2, and leads respectively either C or D, point A from O1 would have a different history from point A from O2, therefore, they would be 2 separate points. This is supported on screen that the TARDIS' explosion would have never happened in the new timeline. For the Doctor from C to have adventures with River then travel to any point in O2B would be ridiculous in that O2B excludes all possibilities where the Doctor exists. So in actual fact the timeline looks like this: | |||
\O1 /C | |||
\ / | |||
\ A1 B1 / | |||
--------------- | |||
--------------- | |||
/ A2 B2 \ | |||
/ \ | |||
/O2 \D | |||
A1B1 and A2B2 must be mutually exclusive. In other words, making it neater: | |||
O1 A1 B1 C | |||
--------------------------------------------- | |||
X | |||
--------------------------------------------- | |||
O2 A2 B2 D | |||
the point X or B1 or B2 is where the accident occured that the Doctor crosses the timeline due to Amy's wedding that brought the timeine O1C to existence....However, the current timeline that the Doctor is on is O1C, which excludes all possibilities of his inexistence states on the timeline, and therefore, O1C does not and cannot overlap O2D. To say that the Doctor can travel from a point on O1C to a point on O2D is to say that the TARDIS can travel across possibilities, simply put, it is similar to saying that when the Doctor is faced with a non-life-threatening situation, if he makes the wrong choice, he can use the TARDIS to travel to a future on the timeline where he made the right choice (not simply undoing the mistake but actually travelling to a potential future that contradicts with the current one). --[[Special:Contributions/222.166.181.59|222.166.181.59]] 06:50, August 4, 2010 (UTC) | |||
